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Block falling on Spring

  1. Oct 12, 2004 #1
    A 2.0 kg block is falling at a speed of 11 m/s and is 18 meters above the spring. The spring constant is 4000 N/m, to the nearest hundredth of a meter what height will the block rise after it hits and leaves the spring?


    Help please! I can find the kinetic energy of the falling block by using... K=.5mv^2 ..... I don't know how to go from there! Help!
     
    Last edited: Oct 13, 2004
  2. jcsd
  3. Oct 13, 2004 #2
    Law of conservation of energy :
    The total energy at the beginning = The total energy at the end
    [tex]\frac{1}{2}mv^2+mgh_1=mgh_2[/tex]
    where
    v=the block initial speed(initial state)
    h1=the block height relative to the spring(initial state)
    h2=the maximum height the block will reach (relative to the spring)ie v =0 (final state)
     
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