A 9.3 kg block is dropped onto a spring of spring constant 1086 N/m from a height of 800 cm. When the block is momentarily at rest, the spring has been compressed by 50 cm. Find the speed of the block when the compression of the spring is 10 cm. The acceleration of gravity is 9.81 m/s^2. Answer in units of m/s. My attempt: Ki + Ui = Kf + Us Ki = o so... Kf = Ui - Us 1/2 mv^2 = mgh - 1/2kx^2 v = (sqrt)mgh - 1/2kx^2/2m v = (sqrt)(9.3)(9.81)(8) - 1/2(1086)(.1)^2/2(9.3) v= 6.240838447m/s which is wrong.