# Homework Help: Block movement

1. Feb 11, 2010

### MisterOL

1. The problem statement, all variables and given/known data
Blocks A and B have mass of Ga and Gb respectively. Wire has no mass, it starts moving so that B has constant speed downward

2. Relevant equations
1.Find μ (frictionkoeficient) regarding GA og GB.
2.When system start moving a cat with weight Ga jums on block A and system stops ( falls into equilabration ) Show that acceleration is proven by this formula :
a= - (μGA / (2GA + 2GB) ) * g

3. The attempt at a solution

2. Feb 11, 2010

### MisterOL

heres the pic to describe prob

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3. Feb 11, 2010

### Lok

Start by enumerating the forces that act upon the two blocks. Ignore the cat for now.

4. Feb 11, 2010

### MisterOL

You mean like this ?

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5. Feb 11, 2010

### Lok

I mean Block A: gravity, friction ....... and later a cat
Block B : gravity

In order to unify them you place them in an equation:

Ffriction=Fgravity

Ffriction=μGag

Fgravity=Gbg

Have fun

6. Feb 11, 2010

### MisterOL

ok here is how I attempt to solve the case
Take a look at the pic

step 1 regarding 3)
Since there is no mass on "wheel" F(res) = m(wheel) * a = 0*a = 0
step 2 regarding 3)
K = $$\sqrt{}((SxS)+(SxS)$$ = $$\sqrt{}2$$ * S
step 3 regarding 1)
newtons 2. in
x direction gives S - R = Ma
y direction gives N = Mg
step 4 regarding 2)
y direction mg - S = ma

if we add S-R = Ma and mg - S = ma we end up with
(M+m)a = mg - R
since R = μ * N and N = Mg
(M+m)a = mg - ( μ * Mg)
-μ * mg - mg - Mg = a (M+m)
μ*mg = Ma + ma - Mg * mg hence
μ = (Ma + ma - Mg * mg)/ mg

whatever I try it does not leave me with Mg or/and mg alone in equasion...

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7. Feb 11, 2010