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Block on frictionless floor

  1. Sep 11, 2008 #1
    Block on frictionless floor!!!!

    A 3.70 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=13.0 N at an angle q= 25.0° above the horizontal, as shown.





    What is the speed of the block 3.70 seconds after it starts moving?

    I have drawn a picture but have no idea what equation to start with. know you solve for aceeleration, then once you have accel. you just solve for Vfinal
     
    Last edited: Sep 11, 2008
  2. jcsd
  3. Sep 11, 2008 #2
    Re: Block on frictionless floor!!!!

    This involves force, mass and a change in speed. What principle of law relates these physcial concepts?
     
  4. Sep 11, 2008 #3
    Re: Block on frictionless floor!!!!

    Newtons 2nd law
     
  5. Sep 11, 2008 #4
    Re: Block on frictionless floor!!!!

    so what now? i know the equations but dont konw how to get acceleration cuase of the theta stuff
     
  6. Sep 11, 2008 #5
    Re: Block on frictionless floor!!!!

    Assuming the vertical component is not sufficient to lift the block off the floor, use the 2nd law with the horizontal component of the applied force.
     
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