1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Block on incline

  1. Oct 28, 2008 #1
    Can someone tell me if I'm doing this problem right?
    1. The problem statement, all variables and given/known data
    Here is the picture of the problem:
    http://i210.photobucket.com/albums/bb23/Kyashii628/block.jpg

    In my FBD, I have Fg pointing down, Fgy perpendicular to the incline and pointing down, Fgx parallel to incline pointing down the ramp (to left), kinetic friction pointing up the ramp (to right), and normal force pointing opposite from Fgy.


    2. Relevant equations
    Fnet= -ma
    fk- Fgx= -ma
    u(Fn)= -ma
    u(345.0615986)= 648.9664808 -240
    u= 1.182397583
     
  2. jcsd
  3. Oct 28, 2008 #2

    PhanthomJay

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    good, but remember in your FBD, that once you resolve Fg into its x and y components, you should 'cross out' the Fg downward force.
    good
    I'm sure you meant u(Fn) = fk
    you have your mg(sin theta)and mg(cos theta) reversed.
    Correct your error and your result should be fine.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Block on incline
  1. Block on an incline (Replies: 2)

  2. Block on an Incline (Replies: 1)

  3. Block on Incline (Replies: 1)

  4. Blocks on Incline (Replies: 1)

  5. Blocks on an Incline (Replies: 37)

Loading...