For simplicity of the solution, the x-axis is chosen to be the axis parallel to the incline, and the y-axis is the axis perpendicular to the incline. In this manner, the applied force F is already in the in the x direction, and when you draw your FBD for the forces (you are missing at least one), a bit of geometry/trig and Newton 1 in the chosen y direction will you give you the relationship between the normal force and weight. Since the applied force is already in the x direction and the normal force in the y direction, it is the weight force that needs to be broken up into its x and y components before applying Newton's Laws. And no, the x-axis is not always the cos, it depends on what angle you are working with and the trig properties of a right triangle.PierceJ said:Homework Statement
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http://i.minus.com/iVbsy2FomprcM.PNG
Homework Equations
F=ma
The Attempt at a Solution
I'm struggling with the normal force and I'm not sure if the component of the force F is the cosine or sine. I see examples where its sine but that doesn't make any sense to me. Isn't the x direction supposed to be cosine?
Fn = mgsinθ
81.2cosθ - Fnμ = 9.23
-Fnμ = -65.897
"Solve Block on Incline HW: F=ma & Fn=mgsinθ" is a physics problem that involves finding the force of a block on an inclined plane, using the equations F=ma (Newton's Second Law) and Fn=mgsinθ (the force of normal force on the block). It is commonly used as a homework question in physics classes.
To solve for the force of a block on an incline, you need to use the equation F=ma, where F is the force, m is the mass of the block, and a is the acceleration. You also need to use the equation Fn=mgsinθ, where Fn is the force of the normal force on the block, m is the mass of the block, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the incline. By setting F=ma equal to Fn=mgsinθ and solving for F, you can find the force of the block on the incline.
Newton's Second Law, also known as the Law of Force and Acceleration, states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In other words, the more force applied to an object, the greater its acceleration will be, and the more massive an object is, the less it will accelerate under the same force.
The normal force is the force that a surface exerts on an object that is in contact with it. It is always perpendicular to the surface and prevents the object from falling through the surface. In the context of "Solve Block on Incline HW: F=ma & Fn=mgsinθ," the normal force is the force that the inclined plane exerts on the block to keep it from sliding down the incline.
The force of the normal force is equal and opposite to the force of gravity in a static situation (when the block is not moving). In other words, the normal force is the force that balances out the force of gravity to keep the object in place. In the context of "Solve Block on Incline HW: F=ma & Fn=mgsinθ," the force of the normal force is equal to mgsinθ, where m is the mass of the block, g is the acceleration due to gravity, and θ is the angle of the incline.