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## Homework Statement

A block of mass 19.0 kg is sliding down an inclined plane. Due to friction between the block and the plane the block is moving at constant speed. If the coefficient of kinetic friction is 0.24), what is the angle of the plane with respect to the horizontal ?

m = 19kg

mu = .24

theta = ?

## Homework Equations

Fk = mu*Fn

Fn = g sin theta

## The Attempt at a Solution

I'm confused about the hint of the block moving with a constant speed due to friction.. Because that means that the net force is 0, so how can I calculate this if one of the forces is equal to 0?? I can't get the normal force without the angle and I can't get the friction force without the normal force.. Can anybody help me out with what that clue implies?

Thanks!