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Block suspended in water

  1. Jan 9, 2008 #1
    A 10.5 kg block of metal measuring 12 cm 10 cm 10 cm is suspended from a scale and immersed in water. The 12.0 cm dimension is vertical and the top of the block is 5.25 cm below the surface of the water.
    (a) What are the forces acting on the top and on the bottom of the block? (Use P0 = 1.0130 105 N/m2.)
    (b) What is the reading of the spring scale?

    ATTEMPT AT SOLUTION
    (a) The forces acting on the top of the block is:
    (0.1m)*(0.1m)*(P0+1000*9.8*0.0525 N/m^2)
    = (1.0130e3+5.1)N = 1.0181e3 N
    and on the bottom of the block is:
    (0.1m)*(0.1m)*(P0+1000*9.8*0.1725 N/m^2)
    = (1.0130e3+16.9)N = 1.0299e3 N

    (b) I'm stuck on this one
     
  2. jcsd
  3. Jan 9, 2008 #2
    (b) The block displaces the mass of the water that would have taken that space. Start there.
     
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