Board on Ice 1. A person of mass M is standing at one end of a board of mass m and length l. The board rests upon a frictionless ice surface and it's mass is uniformly distributed along its length. Calculate how far from the person, d, the centre of mass is of the system. The person then walks to the centre of the board and stops (assuming friction is enough). How far from his starting position (relative to the ice surface) has he moved? 2. centre of mass = 1/M[tex]\Sigma[/tex]mr 3. The attempt at a solution All right, the centre of mass is easy to calculate and it's just (ml)/(2(M+m) and I didn't have problems with that. It's the next part which I am unsure of the correct answer. My friends have got an answer of (ml)/(2(M+m) as his total distance moved but I get a slightly different answer of (l/2)(1 - (m)/(M+m)). My reasoning is that it has to be slightly less then (l/2) as he walks that distance on the board but the board has moved in the opposite direction so the distance from the original starting point is slightly less. The answer of (ml)/(2(M+m)) seems obvious and I'm not 100% it's that or am I just over thinking a simple question? Thanks.