A: A boat capable of making 11.0 km/h in still water is used to cross a river flowing at speed of 3.0 km/h. At what angle (in o) must the boat be directed (from the perpendicular to the shore) so that its motion will be straight across the river?
B: What is the resultant speed relative to the shore?
I'm not sure of the Exact Equations.. Possibly
Ax = A*cos(Theta) Ay = A*sin(Theta)
Bx = B*cos(Theta) By = B*sin(Theta)
Ax+Bx=Cx .. or Ax-Bx=Cx
(I'm at work right now, I forgot the last equation .. Ay/Ax = The tangent of Theta ? By/Bx)
The Attempt at a Solution
For my solution I drew a vector triangle. One directly North, one at the head of this vector going to the right (east) .. and then a resultant line connecting these two vectors. Mainly I just divided 11/3 and took the tangent of this, but couldn't find the correct answer. I can't really attempt the 2nd problem without the way to do the first.
Thanks in advance for the help :)