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YummyPotato
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I tried looking at the other threads on this but they seem incomplete.
I would like someone to check my work.
Two boats are heading away from shore. Boat 1 heads due north at a speed of 3 m/s relative to the shore. Relative to Boat 1, Boat 2 is moving 40° north of east at a speed of 1.7 m/s. A passenger on Boat 2 walks due east across the deck at a speed of 1.1 m/s relative to Boat 2. What is the speed of the passenger to the shore?
x and y vectors.
I set up vectors for each moving object.
B1x = 0 B2y = 0
B2x = 1.7cos(40°) B2y = 1.7sin(40°)
Px = 1.1 Py = 0
I added the x and y components
Rx = 0 + 1.302 + 1.1 Ry = 0 + 1.09 + 0
= 2.402 = 1.09
Sp^2 = (2.402)^2 + (1.09)^2
Sp ≈ 4.74 m/s.
I would like someone to check my work.
Homework Statement
Two boats are heading away from shore. Boat 1 heads due north at a speed of 3 m/s relative to the shore. Relative to Boat 1, Boat 2 is moving 40° north of east at a speed of 1.7 m/s. A passenger on Boat 2 walks due east across the deck at a speed of 1.1 m/s relative to Boat 2. What is the speed of the passenger to the shore?
Homework Equations
x and y vectors.
The Attempt at a Solution
I set up vectors for each moving object.
B1x = 0 B2y = 0
B2x = 1.7cos(40°) B2y = 1.7sin(40°)
Px = 1.1 Py = 0
I added the x and y components
Rx = 0 + 1.302 + 1.1 Ry = 0 + 1.09 + 0
= 2.402 = 1.09
Sp^2 = (2.402)^2 + (1.09)^2
Sp ≈ 4.74 m/s.