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- Thread starter Jodi
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MalleusScientiarum

There's a mass change?

- #3

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I guess so. That's what confuses me about the question. I don't know how to incorporate the mass into it. Does anyone know how to do this? Thanks.

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James R

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What's the energy change?

Next, use [itex]E=mc^2[/itex].

Next, use [itex]E=mc^2[/itex].

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Ok, so I find the energy change by doing E of upper state - energy of lower state right? So I get (-0.2) - (-0.5) = 0.3 After I find this energy change, how do i find the decrease in mass? If I use E=mc^2, I plug in 0.3 into E and 1.00794 into m? What am I solving for? I'm confused. Thanks for your help.

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BJ

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James R

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If your energies are in eV, the conversion is: [itex]1 eV = 1.6 \times 10^{-19} J[/itex]

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