Hi; Could someone please help me with this question: By what fraction does the mass of an H atom decrease when it makes an n=7 to n=5 transition? How would I go about this question? Thank you.
Ok, so I find the energy change by doing E of upper state - energy of lower state right? So I get (-0.2) - (-0.5) = 0.3 After I find this energy change, how do i find the decrease in mass? If I use E=mc^2, I plug in 0.3 into E and 1.00794 into m? What am I solving for? I'm confused. Thanks for your help.
As per [itex]E=mc^2[/itex] , Mass is the condensed form of energy . So whenever energy is released from particle , it is accompanied by a small mass change. So calculate the energy change from one state to another , and then equate the energy change with [itex]mc^2[/itex].
You're trying to find m. c is the speed of light, which is [itex]3 \times 10^8[/itex] m/s. If you want m in kilograms, you need E in Joules. Your 0.3 is not in Joules, so you'll need to convert it.
If your energies are in eV, the conversion is: [itex]1 eV = 1.6 \times 10^{-19} J[/itex]