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Bohr model of hydrogen atom

  1. Oct 5, 2008 #1
    1. The problem statement, all variables and given/known data

    4-16:
    if the angular momentum of the Earth in its motion around the sun were quantized like a hydrogen electron according to equation L=mvr=(nh)/2Π, what would Earth's quantum number be? How much energy would be released in a transition to the next lowest level? would that energy release (presumably as a gravity wave) be detectable? what would be the radius of that orbit? (radius of earth's orbit is 1.5x10^11 m

    2. Relevant equations



    3. The attempt at a solution
    don't even know where to start!! :(
     
  2. jcsd
  3. Oct 5, 2008 #2
    Try finding out what n is using the physical characteristics of the Earth.
     
  4. Oct 5, 2008 #3
    ok so i set nh/2pi equal to L which is 7.27e-5 rad/s and i solved for n. I got 6.2e29.
    for the next part with the energy, i have this equation: [m(k^2)(z^2)(e^2)]/[(2h^2)(n^2)]
    but i don't know what i would use for z. when i use z=1 i get that E= 7.7e-40 J but that just seems very wrong.
     
  5. Oct 6, 2008 #4
    I believe we need to find out how much energy it would take to go from n to n-1. So find the energy at E(n) and subtract E(n-1). See if that gives you something more reasonable.
     
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