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Bohr model question

  1. Oct 6, 2007 #1
    1. The problem statement, all variables and given/known data
    Light of wavelength 410.7 nm is observed in emission from a hydrogen source. a) what transition between hydrogen bohr orbits is responsible for this radiation? b) to what series does this transition belong to?


    2. Relevant equations


    1/lambda=Z^2 *R(1/n^2-m^2) ,

    n being the final transition and m being the initial transition state. R is the Rydberg constant and the Rydberg constant for hydrogen is 1.096776*10^7 m^-1 and Z being the atomic number.
    3. The attempt at a solution

    Since the the wavelength is light , I know that its going to be in the visible spectrum of the E-M spectrum and the Balmer series is always part o the visible spectrum. the initial transition energy state in the balmer series is always m=2. Therefore since I know the initial transition state , R , Z and the wavelength , I thought I could find the n, the final transition state. here are my calculations below:

    1/lambda)*1/(R)= (1/n^2-1/m^2) =>(1/(4.10e-7 m))*(1/(1.096776e7 m^-1))= (1/(2^2)-1/(m^2)) => .2224=(1/4-1/(m^2))=> -1/m^2 = -(.222-.25) => m^2= 1/.028 = 5.97 m = 6
     
  2. jcsd
  3. Oct 6, 2007 #2

    learningphysics

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    Homework Helper

    Looks right. But the final state, n = 2... and you're finding m which is the initial state... so the initial state is m = 6.
     
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