- #1

- 20

- 0

(a) λ(Kα) = 79.8832 pm

(b) λ(Kβ) = 67.401142 pm

(c) λ(Kγ) = 63.90653 pm

(d) The series limit is _____ pm

So I have solved parts a-c. For part d, the series limit, I tried solving using the following formula:

1/lambda=Z^2*R(1/(nl)^2-1/(nu)^2), where nl=1, nu=infinity, Z=40 so it reduced to:

Lambda=1/(Z^2R)= 56.9543545pm, but this answer is wrong. Can anyone see where I'm going going wrong?