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Bohr Model question

  1. Jun 5, 2008 #1
    Calculate the three longest wavelengths and the series limit for the K-shell x-ray series of the zirconium atom.
    (a) λ(Kα) = 79.8832 pm
    (b) λ(Kβ) = 67.401142 pm
    (c) λ(Kγ) = 63.90653 pm
    (d) The series limit is _____ pm

    So I have solved parts a-c. For part d, the series limit, I tried solving using the following formula:
    1/lambda=Z^2*R(1/(nl)^2-1/(nu)^2), where nl=1, nu=infinity, Z=40 so it reduced to:
    Lambda=1/(Z^2R)= 56.9543545pm, but this answer is wrong. Can anyone see where I'm going going wrong?
     
  2. jcsd
  3. Jun 6, 2008 #2

    dynamicsolo

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    At a guess, I'd say you may have punched something into your calculator wrong for part (d). Isn't 3/4 of 79.88 more like 59.91 ?
     
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