1. The problem statement, all variables and given/known data A steel tank with a volume of 5 m^3 contains saturated R-134a at 10 Celcius. The liquid is then boiled away and disappears at 50 Celcius. What is the final pressure? How much liquid was boiled away? 2. Relevant equations PV=nRT 3. The attempt at a solution I pretty much looked at the tables for the numbers in the back of my book. Since at first the tank had the following properties: T=10 C P=? V=5 m^3 and then: T=50 C P=? V=5 m^3 I assumed that the substance R-134a was saturated and look at the values in the table and found that the pressure at first was 415.8 KPa and after was 1318.1 KPa. So I'm assuming that the final pressure is 1318.1 KPa. For the amount of liquid, I took the different of the specific volume (Vf) of the saturated liquid and found it to be 0.000908 - 0.000794 = 0.000114 (m^3)/Kg Am I making the right assumptions?