Boiling point/freezing point

[metalmagik]

Homework Statement

If a temperature scale were based on the freezing point (5.5 C) and boiling point (80.1 C) of benzene and the temperature difference between these points was divided into 50 units (called X), what would be the freezing and boiling points of water in X?

Homework Equations

No idea

The Attempt at a Solution

What does this question even mean? Please help!

 

[Borek]

It is about converting between different temperature scales. You are told how the new scale is constructed - its zero is at 5.5 deg C, there are 50 X between 5.5 and 80.1 deg C. You have to find out a way of converting between deg C and X, just like you convert between F and C.

 

[Blueshift5]

I can provide a clarification and a solution to this question. The question is asking about a hypothetical temperature scale based on the freezing and boiling points of benzene, a common organic compound. This scale divides the temperature difference between the two points into 50 units, called X. The freezing point of benzene is 5.5 C and the boiling point is 80.1 C, so the temperature difference is 80.1 - 5.5 = 74.6 C. Dividing this by 50 units (X) gives us 74.6/50 = 1.492 C per unit.

Now, we need to determine the freezing and boiling points of water on this scale. Water's freezing point is 0 C and its boiling point is 100 C on the Celsius scale. To convert these values to the new scale, we need to find out how many units (X) correspond to 1 C on the Celsius scale. This can be done by dividing 1 C by 1.492 C per unit, giving us 0.67 units (X) per 1 C.

To find the freezing point of water on the new scale, we multiply 0 C by 0.67 units (X) per 1 C, giving us 0 units (X). Therefore, on this new scale, the freezing point of water is 0 units (X). Similarly, the boiling point of water on the new scale can be found by multiplying 100 C by 0.67 units (X) per 1 C, giving us 67 units (X). Therefore, the boiling point of water on this new scale is 67 units (X).

In conclusion, on this hypothetical scale based on the freezing and boiling points of benzene, the freezing point of water is 0 units (X) and the boiling point is 67 units (X). I hope this helps clarify the question and provides a solution.