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Boltzmann equation

  1. Oct 12, 2011 #1
    Why I can't calculate the same answer as the solution below? I use the value as what the below solution showed.

    Q:
    Where Nj is the number of atoms in excited state, No is the number of atoms in the
    ground state, Pj and Po are constants determined by the number of states having equal
    energy at each quantum level, Ej is the energy difference between excited and ground
    states, K is the Boltzmann constant, and T is the absolute temperature. To understand
    the application of this equation let us consider the situation of sodium atoms in the 3s
    state (Po = 2) when excited to the 3p excited state (Pj = 6) at two different
    temperatures 2500 and 2510K. Now let us apply the equation to calculate the relative
    number of atoms in the ground and excited states:
    Usually we use the average of the emission lines from the 3p to 3s where we have two
    lines at 589.0 and 589.6 nm which is:

    Solution:
    λ = (589.0+589.6)/2 = 589.3 nm
    Ej = hc/λ
    Ej = (6.6256x10-34 J s x 2.998x1010 cm s-1)/{(589.3 nm x (cm/ 107 nm)}
    Ej = 3.37x10-19 J
    Nj/No = (6/2) exp {(-3.37x10-19 J/(1.38x10-23 J K-1 x 2500 K)}
    Nj/No = 1.72x10-4
     
  2. jcsd
  3. Oct 12, 2011 #2

    Borek

    User Avatar

    Staff: Mentor

    Hard to tell where your problem is, calculations look correct and I got the same result from these numbers. Perhaps you are keying them wrong into calculator, or misunderstanding the notation. 2.998x1010 means 2.998x1010 and probably should be entered as 2.998e10 or something like that - details will depend on what (program, calculator model) you use.
     
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