1. Oct 12, 2007

### kingwinner

Bolzano-Weierstrass Theorem: Let S C R^n. Then S is compact (bounded and closed) iff every sequence of points in S has a convergent subsequence whose limit lies in S.

I am completely completely lost when reading this example.

1. Why do we need 2 cases?

2. How are the 2 cases different?

3. For the second case, how come the subscripts of x_n_j and L_i_j are different? (n and i)

4. I don't understand the solution at all, can somebody please explain it step-by-step what is happening?

I really want to understand this example! Thanks a lot!

2. Oct 12, 2007

### Dick

Did you draw a picture of the geometry? It would really help. You have an infinite number of line segments which are getting shorter and shorter and closer and closer to the origin. And you do need two cases, one where an infinite number of points are on a single segment (in which case the limit might not be (0,0)) and the case where the points are on an infinite number of lines, in which case the limit is (0,0). Though a single sequence may contain both types of subsequences. Draw a picture and think about it again.