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Boolean Algebra help Please

  1. May 14, 2009 #1
    Digital Logic is blowing my head off! I can't understand a thing.

    I had a question in which I was supposed to simplify the function

    Code (Text):
    F= A'+B'+(A+B).B'.C
    apperently this simplify to 1.

    Here's what I managed to do:

    Code (Text):
    F= A'+B'+[(A.B')+(B.B')].C by Distribution

    F= A'+B'+(A.B').C by Tautology

    F= A'+B'+A.B'.C by Distribution
    according to the answer the next step get

    F = A+A'+B'

    F=1

    however I have no idea what he's done or how to get there.

    Any help would be appreciated

    Regards,
    Bruynz.

    I hope this is the right section
     
    Last edited: May 14, 2009
  2. jcsd
  3. May 14, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi Bruynz! Welcome to PF! :smile:
    Do not adjust your mind …

    reality is at fault! :biggrin:

    The question is obviously wrong. :rolleyes:
     
  4. May 14, 2009 #3
    F= A'+B'+(A+B).B'.C
    F = A' + B' + A.B'.C
    F = A' + B' + A.C
    F = A' + B' + C

    Yeah, they did something jive near the last step. I'm pretty sure that what I have down is the final answer. You can go back to the original and construct its truth table to trivially show it is no tautology.
     
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