- #1

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**show that x'yc+xy'c+xy = yc + xc + xy**

## The Attempt at a Solution

- my first attempt at the solution was this:

c(x'y+xy')+xc >>> c(y+x)+xc >>> yc+xc+xy

I can't remember if that is valid or not. I seem to remember that A'B=B, but not sure. Can somebody please help me?