# Boolean-Could someone check my answer?

1. Feb 4, 2005

### cact

I was just wondering if someone could check my answer for simplifiying the below question.

$\bar{(A+B)}$(A+B)= X the first (A+B) has a continuous bar above it from bracket to braket.

Would this be the correct way to simplifiy it?
($\bar{A}$*$\bar{B}$) + (A+B)= X

$\bar{A}$A$\bar{B}$+A$\bar{B}$B= X

(0)$\bar{B}$+A(0)= X

A$\bar{B}$= X

be the correct steps to simplifiy the problem?

Last edited: Feb 4, 2005
2. Feb 5, 2005

### maverick280857

If only the first bracket has the bar over it then there seems to be a mistake in the first step. The sum can be converted into the product using deMorgan's Laws but you can do so only for the expression under the bar. So,

$$\vec{A+B} = \vec{A}\vec{B}$$

Now do this all over and you should be through (the brute force method after the first step in most problems isn't a bad idea unless you observe some symmetry or vanishing terms...)

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