- #1
cact
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I was just wondering if someone could check my answer for simplifiying the below question.
[itex]\bar{(A+B)}[/itex](A+B)= X the first (A+B) has a continuous bar above it from bracket to braket.
Would this be the correct way to simplifiy it?
([itex]\bar{A}[/itex]*[itex]\bar{B}[/itex]) + (A+B)= X
[itex]\bar{A}[/itex]A[itex]\bar{B}[/itex]+A[itex]\bar{B}[/itex]B= X
(0)[itex]\bar{B}[/itex]+A(0)= X
A[itex]\bar{B}[/itex]= X
be the correct steps to simplifiy the problem?
[itex]\bar{(A+B)}[/itex](A+B)= X the first (A+B) has a continuous bar above it from bracket to braket.
Would this be the correct way to simplifiy it?
([itex]\bar{A}[/itex]*[itex]\bar{B}[/itex]) + (A+B)= X
[itex]\bar{A}[/itex]A[itex]\bar{B}[/itex]+A[itex]\bar{B}[/itex]B= X
(0)[itex]\bar{B}[/itex]+A(0)= X
A[itex]\bar{B}[/itex]= X
be the correct steps to simplifiy the problem?
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