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Boolean simplification

  1. Nov 30, 2011 #1
    ABC + AB' . ( A' C') + A'BC

    I am confused in AB' . ( A' C')

    the multiplication would be AA'B'C' OR AA'C'+A'B'C'
     
  2. jcsd
  3. Nov 30, 2011 #2

    ehild

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    It is AA'B'C'.

    ehild
     
  4. Nov 30, 2011 #3
    Abc + ab' . ( a' c') + a'bc

    abc + aa'b'c' + a'bc

    abc + b'c' + a'bc ( aa' = 0)

    bc(a + b'c' +a')

    bc (a+a'+b'c') as a+a' = 1

    bc( b'c')

    bb'cc'

    0

    is this is right
     
  5. Nov 30, 2011 #4

    ehild

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    As aa'=0 the second term cancels. You have abc+a'bc. Continue from here.

    ehild
     
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