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- Thread starter desmond iking
- Start date

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- #2

jedishrfu

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Is this a homework assignment?

- #3

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no, i am studying myself during the holiday.

Is this a homework assignment?

- #4

jedishrfu

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Boolean algebra rules are the same as ordinary algebra with the added concepts X=X'=1 and X.X'=0 and X=0 means X=false and X=1 means X=true. Engineers start with a truth table for a circuit, construct boolean expressions, reduce them down using boolean algebra ruls and then construct a circuit from the reduced expressions.

- #5

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i only managed to reduce it to XY +Y' +X'Y

Boolean algebra rules are the same as ordinary algebra with the added concepts X=X'=1 and X.X'=0 and X=0 means X=false and X=1 means X=true. Engineers start with a truth table for a circuit, construct boolean expressions, reduce them down using boolean algebra ruls and then construct a circuit from the reduced expressions.

here's my working:

(X'Y') + (X'Y) + (XY') + (XY)

=XY +Y'(X' +X ) +X'Y

= XY +Y' +X'Y

- #6

jedishrfu

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what about the 1st and 3rd term? they have a common Y.

- #7

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what about the 1st and 3rd term? they have a common Y.

continue form the previous post , i still didnt get the ans

XY +Y' +X'Y = Y(X +X') +Y' = Y+Y'

- #8

NascentOxygen

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Hi Desmond. No one can explain it. It's a misprint.Can someone please explain why the F( X, Y ) is XY' + XY ?

It is just the exclusive OR function, X'Y + XY'. It doesn't simplify, except you can write it as X ⨁ Y.

Good luck with your self-study. http://thumbnails112.imagebam.com/37333/0363e9373324851.jpg [Broken]

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- #9

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- #10

NascentOxygen

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It's a misprint. F(X,Y) is true when either of these is true: X'Y or XY'

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