Bored in math class, figured out mixture problems.

  • Thread starter Blahness
  • Start date
  • #1
106
0

Main Question or Discussion Point

Mixture problem example: You need parts of a 30% chlorine and 55% chlorine mixture to make 100 gallons of a 40% chlorine. mixture.

To figure out what the ratio of 30 to 55 is: 55% - 40% = 15 parts needed of 35% mixture, 40% - 30% = 10 parts of 50% mixture.

15 parts of 30% reduces to 3 parts of 30%
10 parts of 55% reduces to 2 part of 55%

Then you take the ratio of the two (3:2), and multiply the ratio to get 60 gallons of the 30%, and 40 gallons of the 55%. (60:40)

Make sense to anyone? I'm not sure how I do the ratio part for fraction answers, but I have the beginning part out.

If already done, sue me. I figured it out in my own spare 10 minutes of class.
 

Answers and Replies

  • #2
1,425
1
It's easier to understand if you proceed that way:

The mixture z is composed of mixture y and mixture x. We know that z=100 Gallons. That gives x+y=100. You want to find x and y such as 30x/100 + 55y/100=40

So y=100-x

30x + 55(100-x)/100=40
30x + 5500 -55x=4000
-25x=-1500
x=60

so y=40
 

Related Threads for: Bored in math class, figured out mixture problems.

Replies
2
Views
1K
  • Poll
  • Last Post
2
Replies
39
Views
8K
Replies
3
Views
2K
  • Last Post
Replies
3
Views
2K
Replies
2
Views
2K
Replies
2
Views
1K
Top