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**[SOLVED] Bouyant force**

**1. A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm (0.04 m) in the water. What is the weight of the truck?**

**2. F(sub: B) = F(sub: g)[displaced fluid] = m(sub: f)g**

(magnitude of bouyant force = weight of the fluid displaced)

F(sub: B) = F(sub: g)[object] = m(sub: o)g

bouyant force = weight of floating object

m = ρV

(mass = density × volume)

(magnitude of bouyant force = weight of the fluid displaced)

F(sub: B) = F(sub: g)[object] = m(sub: o)g

bouyant force = weight of floating object

m = ρV

(mass = density × volume)

**3. Well, the voulme of the boat is (4.0 m)(6.0 m)(0.04 m) = (0.96 m³); I mean, the volume of the displaced water is that. ;)**

Density of fresh water = 1.00 × 10³ kg/m³

F = ρV(g)

F = (1.00 × 10³ kg/m³)(0.96 m³)(9.81 m/s²)

F = 9.4 × 10³ N

Density of fresh water = 1.00 × 10³ kg/m³

F = ρV(g)

F = (1.00 × 10³ kg/m³)(0.96 m³)(9.81 m/s²)

F = 9.4 × 10³ N

Am I correct?

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