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Bouyant force

  1. Feb 10, 2008 #1
    [SOLVED] Bouyant force

    1. A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm (0.04 m) in the water. What is the weight of the truck?



    2. F(sub: B) = F(sub: g)[displaced fluid] = m(sub: f)g
    (magnitude of bouyant force = weight of the fluid displaced)

    F(sub: B) = F(sub: g)[object] = m(sub: o)g
    bouyant force = weight of floating object

    m = ρV
    (mass = density × volume)




    3. Well, the voulme of the boat is (4.0 m)(6.0 m)(0.04 m) = (0.96 m³); I mean, the volume of the displaced water is that. ;)

    Density of fresh water = 1.00 × 10³ kg/m³

    F = ρV(g)
    F = (1.00 × 10³ kg/m³)(0.96 m³)(9.81 m/s²)
    F = 9.4 × 10³ N


    Am I correct?
     
    Last edited: Feb 10, 2008
  2. jcsd
  3. Feb 10, 2008 #2

    mgb_phys

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    Homework Helper

    Correct - and an extra bonus point for quoting the weight of the truck not it's mass.
    Although you will probably get the answer marked wrong by some dumb online marking system that expects mass.
     
  4. Feb 10, 2008 #3
    All right! Thanks. :)

    Problem solved!!!

    EDIT: Ermmm... How do I mark it solved?
     
  5. Feb 10, 2008 #4
    Found it. :)
     
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