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Box falling on a spring

  1. Oct 7, 2007 #1
    1. The problem statement, all variables and given/known data
    A 2.14 kg block is dropped from a height of 43.6 cm onto a spring of force constant 18.6 N/cm. Find the maximum distance the spring will be compressed.

    I know that the mass is 2.14 kg, the force constant of the spring is K=1860 N/m.

    I assume the final velocity, the final height of the block after being dropped, and the final distance the spring will be compressed are 0.


    2. Relevant equations
    U+K=0
    v^2=v(0)^2+2AS


    3. The attempt at a solution
    To find the initial velocity, I use the constant acceleration equation:

    0=V(0)^2-19.7(.436); V(0)=2.92m/s

    Since I know (or assume) a conservative force, I use the equation:

    U+K=0

    mgh+(1/2)mv(0)^2+(1/2)kx^2=0

    2.14(-9.8)(.436)-.5(2.14)(2.92)^2+(1/2)(1860)x^2=0

    x=.139 m = 13.9 cm

    The book got 11.1 cm. Can anyone tell me what I did wrong and how to do the problem correctly? Must help is appreciated. Thanks!
     
  2. jcsd
  3. Oct 7, 2007 #2

    Doc Al

    User Avatar

    Staff: Mentor

    The initial (and final) velocity is zero. What you found is the speed at which the block hits the spring. That would be OK, but then you messed up the energy conservation.

    It will be much easier if you just stuck with energy conservation from start to finish. Hint: the total distance dropped is not just 43.6 cm.
     
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