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Box on a Frictionless Incline

  1. Jan 26, 2010 #1
    1. The problem statement, all variables and given/known data

    A 12 kg box is being held on a 23 degree frictionless incline. Find the box's equation once released.

    2. Relevant equations

    Net force=ma


    3. The attempt at a solution

    12kg x 9.8m/s = 117.6 N

    (Fpull-mgsin23)= ma

    sub. known values in

    117.6 N-(117.6N (sin23))= 12kg x a

    a[tex]\rightarrow[/tex]equals about 6.0 m/s

    I know I am doing something wrong. I am reviewing for a final, and am trying to remember things. Please help me figure out what I did wrong.
    THANK YOU!!! :)
  2. jcsd
  3. Jan 26, 2010 #2
    i think its cos23 instead of sign.
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