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Boyle Law help

  1. Jan 14, 2004 #1
    can anyone tell me the steps to do this problem?

    You are given a gas that you measure under a pressure of 720 mmHg. When the pressure is changed to 760 mmHg, the volume becomes 580 mL. What was the original volume of the gas?

    I don't know how to do this problem. thanx!
  2. jcsd
  3. Jan 14, 2004 #2
    Its this simple ratio:

    [tex]\frac{P_{1}}{V_{1}} = \frac{P_{2}}{V_{2}}[/tex]

    so to find [tex]V_{1}[/tex]

    [tex]V_{1} = \frac {P_{1}V_{2}}{P_{2}}[/tex]
    Last edited: Jan 14, 2004
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