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Boyle's Law Question

  1. Apr 17, 2009 #1
    1. The problem statement, all variables and given/known data
    A diver dives to a depth of 40 m in fresh water where he releases a toy balloon of volume 10 cm^3. What will be the size of the balloon when it reaches the surface? (The pressure increass at a rate of 1 atmosphere for every 10 m descent in fresh water)


    2. Relevant equations

    P1V1=P2V2



    3. The attempt at a solution

    P1= 4 atm
    V1= 10 cm^3
    P2= ?
    V1=?

    I just dont know how to find the pressure when it reaches the surface... what would the pressure be?
    Thankyou:)

    Kind regards
     
  2. jcsd
  3. Apr 17, 2009 #2

    CompuChip

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    Science Advisor
    Homework Helper

    The pressure at the surface of the water is the outside pressure, which you can probably assume to be 1 atm. So, more or less by definition of the unit "atmosphere", P2 = 1 atm.
    You might want to check your value for P1, however.
     
  4. Apr 17, 2009 #3
    thankyou very much:) that makes sense:)
     
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