(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Atmospheric pressure is 100 kPa and a depth of 1m in water is equivalent in pressure to 10 kPa. A jam tin, open end down, is forced under water until the water half fills the can. At this stage, how far beneath the surface is the can? (ans is 10 m)

2. Relevant equations

I DONT'T UNDERSTAND WHY 10 metres! T_T

3. The attempt at a solution

So from what I know, I must use Boyle's Law.

P1 = 100 kpa

P2 = ?

V1= ?

V2 = 1/2 V1

P1V1=P2V2

100V1=P2(1/2 V1)

100V1=1/2 P2V1 <---Don't the V1's cancel out?

200=P2

using ratio's:

[tex]\frac{1 m}{10 kPa}[/tex] = [tex]\frac{x}{200 kPa}[/tex]

x=20 m

Why is my answer different from my worksheet (10m) ??

Any help is greatly appreciated!

Thanks

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# Homework Help: Boyle's Law

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