- #1

- 160

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[tex] \delta \psi = 0 [/tex]

where [tex] \psi [/tex] is a fermion field.

Could somebody explain why this is the BPS equation?

Thanks!

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- Thread starter ismaili
- Start date

- #1

- 160

- 0

[tex] \delta \psi = 0 [/tex]

where [tex] \psi [/tex] is a fermion field.

Could somebody explain why this is the BPS equation?

Thanks!

- #2

- 2

- 0

I know vaguely, that the supersymmetry algebra can be extended by a central charge term, that effectively break some of the supercharges and thus truncate the supermultiplets. There is a bound, called the BPS bound and states that satisfy this bound are BPS states. Can't remember right now much about this bound. Anyways, I guess that the name BPS refers to the fact that you break some of the supersymmetry?

Let me know if you know more by now.

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