Solving Bra-ket Multiplication: <n|(a-+a+)^4|n> = 5n2+5n+3

In summary, the conversation discusses the equation <n|(a-+a+)^4|n> = 5n2+5n+3 and how to prove that the left and right sides are equal. The process is explained using an example of the 4th power and the use of a^+ and a^- operators.
  • #1
crystalplane
11
0
hey guys,

<n|(a-+a+)^4|n> = 5n2+5n+3

I am wondering if some one can show me why left and right side are equal

    Thanks in advance
 
Physics news on Phys.org
  • #2
If it is true, it's simply a matter of doing the work.

[tex](a^ - + a^ + )^2 = (a^ - a^ - + a^ - a^ + + a^ + a^ - + a^ + a^ + )[/tex] for example, so you do the case for the 4th power, you can work out what the result is knowing
[tex]\[
\begin{array}{l}
a^ + \left. {|n} \right\rangle = \sqrt {n + 1} \left. {|n + 1} \right\rangle \\
a^ - \left. {|n} \right\rangle = \sqrt n \left. {|n - 1} \right\rangle \\
\end{array}[/tex]

and any term that doesn't return the ket to |n> can be ignored since it'll go away.
 
  • #3
!

Hello,

I would be happy to explain the solution to this equation. First, let's break down the components of the equation. The <n| represents the bra vector, which is the complex conjugate of the ket vector |n>. The (a-+a+)^4 represents the operator, which in this case is a combination of the annihilation operator (a-) and creation operator (a+), raised to the fourth power. Finally, the |n> represents the ket vector.

To solve this equation, we can use the properties of the annihilation and creation operators. First, we know that the annihilation and creation operators are Hermitian conjugates of each other, meaning that (a-)^† = a+. This allows us to simplify the equation to <n|(a+)^4|n>.

Next, we can use the commutation relation between the annihilation and creation operators, [a-, a+] = 1, to expand the operator (a+)^4. This gives us <n|(a+)^4|n> = <n|(a+)(a+)(a+)(a+)|n> = <n|(a+)(a+)(a+)(a+)|n> = <n|(a+)(a+)^3|n>.

Using the commutation relation again, we can further simplify the equation to <n|(a+)^3(a+)|n> = <n|(a+)^2(a+)^2|n> = <n|(a+)^4|n>.

Finally, we can use the fact that the annihilation and creation operators commute with the bra and ket vectors to simplify the equation to <n|(a+)^4|n> = (a+)4<n|n> = 4<n|n>.

Since <n|n> is equal to 1, we can conclude that <n|(a-+a+)^4|n> = 4. However, the equation provided states that the result is 5n2+5n+3, which is not equal to 4. Therefore, there must be a mistake in the equation or the solution.

I hope this explanation helps. Please let me know if you have any further questions.
 

1. How do you solve bra-ket multiplication?

To solve bra-ket multiplication, you first need to understand the bra-ket notation used in quantum mechanics. A bra represents a vector in the dual space, while a ket represents a vector in the regular space. To solve the equation, you would need to use the rules of linear algebra, such as distributivity and associativity, to manipulate the expression until you can simplify it into a final answer.

2. What is the significance of the equation = 5n2+5n+3?

This equation represents the expectation value of the operator (a-+a+)^4 in the state |n>. The expectation value is a fundamental concept in quantum mechanics and is used to predict the average outcome of a measurement on a quantum system. In this case, the equation tells us that the expected value is equal to 5n^2 + 5n + 3, which can have important implications in understanding the behavior of quantum systems.

3. What is the purpose of using bra-ket notation in quantum mechanics?

Bra-ket notation was introduced by physicist Paul Dirac as a way to simplify and standardize the notation used in quantum mechanics. It allows for a compact representation of vectors and operators, making it easier to perform calculations and express concepts in quantum mechanics. It also allows for a more intuitive understanding of concepts such as the inner product and expectation value.

4. How does bra-ket multiplication differ from regular multiplication?

Bra-ket multiplication follows different rules from regular multiplication, as it involves vectors and operators instead of numbers. For example, in regular multiplication, the order of the operands doesn't matter (e.g. 2 x 3 = 3 x 2), but in bra-ket multiplication, the order of the bra and ket matters (e.g. is not the same as ). Additionally, the result of bra-ket multiplication is a scalar, while regular multiplication results in a product of two numbers.

5. Are there any special cases or exceptions when solving bra-ket multiplication?

Yes, there are some special cases or exceptions that may arise when solving bra-ket multiplication. One common exception is when the operator is non-Hermitian, which means it is not equal to its own conjugate transpose. In this case, the rules of bra-ket multiplication may not apply, and a different approach may be needed to solve the equation. It is also important to consider the compatibility of the bra and ket vectors, as not all combinations will result in a valid calculation.

Similar threads

Replies
8
Views
1K
Replies
16
Views
1K
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Linear and Abstract Algebra
Replies
1
Views
825
  • Quantum Physics
Replies
6
Views
2K
  • Advanced Physics Homework Help
Replies
3
Views
885
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Quantum Physics
Replies
9
Views
2K
Replies
2
Views
857
  • Advanced Physics Homework Help
Replies
1
Views
952
Back
Top