I have a basic question that I have overlooked in the past, given that you have(adsbygoogle = window.adsbygoogle || []).push({});

<psi2|A = lamda2<psi2|, where <| is a bra and lamda2 is the eigenvalue. If you were to multiply the equation by |psi1>, why do you get <psi2|A|psi1> = lamda2<psi2|psi1> and not |psi1><psi2|A = lamda2|psi1><psi2| ? Wouldn't the former defeat the purpose of operator algebra?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Bra-Ket operation

Loading...

Similar Threads - operation | Date |
---|---|

I Operators and vectors in infinite dimensional vector spaces | Mar 2, 2018 |

I How to create the operator of unknown beamsplitter | Feb 27, 2018 |

I Hamiltonian in Schrödinger: necessarily total energy? | Feb 22, 2018 |

I Commuting Operators and CSCO | Feb 20, 2018 |

I Dirac operator explained | Feb 18, 2018 |

**Physics Forums - The Fusion of Science and Community**