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Bragg angle and X-ray Radiation

  1. Mar 19, 2010 #1
    1. The problem statement, all variables and given/known data

    In an experiment with X-ray radiation, you use a continuous radiation from an X-ray pipe. What is the highest energy of the X-ray radiation you can get if the pipe's acceleration voltage is 40 kV? If we use radiation with double the wavelength of the maximum energy we get enough intensity to do a Bragg scatter experiement with a crystal. We get constructive interference at an angle of 30 degrees (Bragg angle). What's the jitter constant (d) in the crystal?



    2. Relevant equations

    We have the Bragg equation:

    2dsin(Θ)=λm

    and the cutoff Equation

    λmin= hc/eV

    3. The attempt at a solution

    Due to the conservation of energy the maximum energy of the radiation is 40 KeV. The cutoff wavelength is thus 31 pm. A photon with energy of at most 40 keV has wavelength of at least 31 pm.

    Then, plugging into the Bragg formula we get:

    2dsin30= 62 pm*m
    2d(1/2)=62 pm * m
    d= 62 pm*m

    Is this correct? If anyone can give any advice it would be much appreciated! Thanks in advance.
     
  2. jcsd
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