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Bragg condition ambiguity

  1. Mar 5, 2009 #1
    Hello, I have a quick question regarding the bragg condition.

    I know that it is most often stated as [tex]2dSin \theta=n\lambda[/tex]

    But I have come across a case (Kittel chp9 pg 255, where it is written as ([tex]\vec{k}[/tex]+[tex]\vec{G}[/tex])[tex]^{2} = k[/tex]

    I cannot really see how the vectorial case is the same as the simpler former one.
    Could someone elucidate?

    Thanks
     
  2. jcsd
  3. Mar 5, 2009 #2

    malawi_glenn

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  4. Mar 5, 2009 #3
    Or look in the same book (Kittel -Chapter 2) where the equivalence of the two formulas is discussed explicitly.
     
  5. Mar 5, 2009 #4

    malawi_glenn

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    good call!
     
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