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Bragg Diffraction

  1. Oct 21, 2014 #1
    Bragg diffraction of microwaves lab.
    Hey guys I have a quick question so for bragg diffraction the formula is 2dsin(theta) = n(lambda).
    So I have to solve for d, which is d = n(lambda)/(2sin(theta)), but here is the problem: I'm not entirely sure what theta is, as I'm using a graph with 2 peak values, so would theta be just the peak value, and the first peak is n = 1, and peak 2 is n = 2?

  2. jcsd
  3. Oct 27, 2014 #2
    Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
  4. Oct 29, 2014 #3
    Hey no problem, thanks for checking that means a lot to me.
    I figured it out eventually, thank you very much though!
  5. Oct 29, 2014 #4
    Yes, the angle in the formula will be the peak value.
    Regarding the order of the diffraction peak, it is possible that the second peak is the second order of the first. But it is not necessary.
    What was your sample?
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