How Do You Calculate the Speed of a Stone in a Sling?

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In summary, David experimented with slings before facing Goliath and found that a sling of length 0.750 m could be revolved at a rate of 10.0 rev/s. When he increased the length to 1.050 m, he could only revolve it 8.00 times per second. The equation used to calculate the speed of the stone is V_t = r x ω. At 10.0 rev/s, the speed is ... m/s and at 8.00 rev/s, it is ... m/s.
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Melchior25
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Homework Statement



Young David who slew Goliath experimented with slings before tackling the giant. He found that he could revolve a sling of length 0.750 m at the rate of 10.0 rev/s. If he increased the length to 1.050 m, he could revolve the sling only 8.00 times per second.



What is the speed of the stone for each rate of rotation?

a) ... m/s at 10.0 rev/s

b) ... m/s at 8.00 rev/s

The Attempt at a Solution



I can probably figure this out but I forgot my book and don't want to guess. Please could you tell me the equation that I use.

Thanks.
 
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  • #2
It is most likely the relationship between angular movement and tangential.
[tex]V_t=r \cdot\omega[/tex]

Casey
 
  • #3
Thanks, I got it.

I just took the circumference and multiplied that by the rotations/sec.
 

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