If x,y,z are the position operators.(adsbygoogle = window.adsbygoogle || []).push({});

Is it true that:

<φ|x|φ> + <φ|y|φ> + <φ|z|φ> = <φ | x+y+z| φ> ?

So that if, for example, one wanted to compute <φ|r|φ> (where r =x+y+z), then they would just have to sum the parts.

I know that for scalars, a and b, we have the following:

(a+b)|φ> = a|φ> + b|φ>

But I don't know for sure if this is related at all to the case for operators (especially when they are sandwiched between the bra and the ket.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Braket notation help

Loading...

Similar Threads for Braket notation help | Date |
---|---|

Momentum operator eigenfunction | Dec 27, 2014 |

Braket operation | Jul 26, 2012 |

Why do people even teach quantum mechanics without braket notation? | Dec 24, 2010 |

Quick Braket notation question | Jan 3, 2010 |

Question about Braket notation | Apr 23, 2009 |

**Physics Forums - The Fusion of Science and Community**