- #1
jhson114
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A car traveling at a speed of vo = 59 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 166 m.
There are 3 parts to this quetions.
1. what is its acceleration during the time it is stopping
2. how long does it take for the car to stop
3. after the car has gone 1/3 of the stopping distance what is its speed
i have answered the first two questions, but i can't answer the last question.
i got -10.5 m/s^2 and 5.6 seconds for first two answer. to get third answer i simply did Vf = Vi + A*deltaT which came out Vf = 59-10.5(5.6/3) = 39.4
first two answers are correct but the third one is wrong. can someone please tell me what I'm doing wrong. thank you
There are 3 parts to this quetions.
1. what is its acceleration during the time it is stopping
2. how long does it take for the car to stop
3. after the car has gone 1/3 of the stopping distance what is its speed
i have answered the first two questions, but i can't answer the last question.
i got -10.5 m/s^2 and 5.6 seconds for first two answer. to get third answer i simply did Vf = Vi + A*deltaT which came out Vf = 59-10.5(5.6/3) = 39.4
first two answers are correct but the third one is wrong. can someone please tell me what I'm doing wrong. thank you