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Branch cut for (lnz)^2

  1. Jun 10, 2013 #1
    1. The problem statement, all variables and given/known data
    It is simply the same as the one for lnz i.e. does it go from 0 to ∞?
    Also, is there any proper way to figure out branch points of a function?

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 10, 2013 #2
  4. Jun 10, 2013 #3
    Do you mean, "Does z go from 0 to ∞?" Your question is unclear, which is why no one will answer.

    Generally, branch cuts can be made fairly arbitrarily as long as they make sense. Though, I personally prefer to use Riemann surfaces because they are more fun for me.
     
  5. Jun 10, 2013 #4

    Office_Shredder

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    Certainly if you have a domain where ln(z) is defined holomorphically, then ln(z)2 is also holomorphic on the same domain
     
  6. Jun 11, 2013 #5
    Ok thanks.
     
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