1. The problem statement, all variables and given/known data An electron has a de Broglie wavelength equal to the diameter of a hydrogen atom in its ground state. What is the kinetic energy of the electron? How does this energy compare with the ground-state energy of the hydrogen atom? 2. Relevant equations λ = h /mv diameter = 2 x bohr radius = 1.06e-10 m 3. The attempt at a solution 1.06e-10 = 6.63e-34/1.67e-27v v = 3.75e3 m/s .5(1.67e-27)(3.75e3)^2 = 1.17e-20 J = .0732 eV Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.