- #1

stunner5000pt

- 1,455

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## Homework Statement

assume that the total downward force exerted at A & B by the leg is 38N. find the weight W, attached on the lower puller

## Homework Equations

please see attached diagram

## The Attempt at a Solution

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i have written roman numerals to help determine which equation refers to which point

at point I

[tex] W = T [/tex]

at point II

in the X direction

[tex] T \cos 25 + F_{1} = F_{A} cos \theta [/tex]

in the y direction

[tex] T \sin 25 = F_{A} \sin \theta [/tex]

at point III

in the X direction

[tex]0=T \cos 20 +T \cos 25 [/tex]

in the Y direction

[tex] T \sin 20 + T \sin 25 [/tex]

at point IV

in the X direction

[tex] T \cos 20 + T \cos 60 = 0 [/tex]

in the Y direction

[tex] -T \sin 20 - T\sin 60 = 0 [/tex]

And that the end of this, can we say that T = 38N?

Please let me know if all the equations are correct?

Thank you for your input and assistance!