# Brushing up on the basics

1. Jan 5, 2014

### matty204359

I feel retarded because I'm not understanding this equation despite getting A's in all my math classes.

$$i(t) = \frac{dq(t)}{dt}$$

some how becomes

$$q(t) = \int^{t}_{t_{0}} i(t)dt + q(t_{0})$$

I'm guessing we apply the integral operator $$\int dt$$ to both sides. so where is the $$q(t_{0})$$ term on the RHS coming from?

Its a charge(q) and current(i) formula as a function of time(t) if that helps make more sense.

Last edited: Jan 5, 2014
2. Jan 5, 2014

### gopher_p

$$q(t) = \int^{t}_{t_{0}} i(t)dt + q(t_{0})$$

is a special case of

$$f(t) = \int^{t}_{t_{0}}f'(t)dt + f(t_{0})$$

which is a corollary to the Fundamental Theorem of Calculus, sometimes referred to as the Net Change Theorem.

3. Jan 6, 2014

### tiny-tim

himatty204359! welcome to pf!
let's rewrite that as

$$q(t) - q(t_{0}) = [q(t)]^{t}_{t_{0}} = \int^{t}_{t_{0}} q'(t)dt$$

(btw, you really ought to have a different variable, eg τ, inside the ∫ )