Bob picks up a bucket of water by a rope and swings it around in a vertical plane. The bucket passes through the top of the circle with a speed v1.
(Note: You may neglect air resistance.)
a.)At point 1 (top of the loop):
How large is centripetal acceleration of the bucket? (Express as a multiple of g.)
ac,1 = · g
How much is the tension in the rope? (Express as a multiple of the bucket's weight.)
T1 = · mg
b.) At point 2 (bucket at same height as the center of the circle):
What is the speed of the bucket? (Express as a multiple of v1.)
v2 = · v1
How large is centripetal acceleration of the bucket?
ac,2 = · g
How much is the tension in the rope?
T2 = · mg
c.) Repeat when the bucket is at point 3 (bottom of the swing):
v3 = · v1
ac,3 = · g
T3 = · mg
The Attempt at a Solution
I figured out the solutions to part a which is 1 and 0. But I'm having a hard time with part b and c. Top of the swing T=mv^2/r + mg. Left of swing T = mv^2/r. Bottom of swing T= mv^2/r -mg. Right?