What will be the pH of a solution that contains 0.100 M CH3COOH and 0.100 M NaCH3COO?Ka = 1.8x10-5
IMPORTANT: THE REACTION IS NOT BETWEEN CH3COOH AND CH3COO-
- My question here is why the ice table was setup as so by the instructor? see below...
The Attempt at a Solution
CH3COOH + H20 ---> CH3COO- + H3O
.100M-x .100m+x +x
Where did the Na go? Why did the Molarity of NaCH3COO = Molarity of CH3COO- ????