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## Homework Statement

20.0 mL of a 0.1 M solution of sodium hydroxide is titrated into 50.0 ml of the 0.14 M HOBr solution. Calculate the pH of the resulting solution.

ph of HOBr is 4.74

Ka is 2.3e-9

## Homework Equations

[H+] = ka(a/b)

-log[h+] = ph

ka*kb=kw

## The Attempt at a Solution

honestly i have no clue how to do this problem. I already know the answer its 8.24, but I haven't a clue how to get it. can someone point me in the right direction?

thanks