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Buffer solution

  1. Apr 7, 2014 #1
    You want to have a ph of 9.55 with a buffer. How many grames of CH3NH3ClO4 would you add to 800 ml of 0.258 M CH3NH2 to do this. Assume volume remains constant. Kb for methylamine is 4.2x10^-4.

    My answer is 320g. Can anyone check this please? I have an exam on buffers very fast. You would do me a great favor.
    I used Henderson to find concentration of methylamine required. Then the number of moles and grams.
     
  2. jcsd
  3. Apr 7, 2014 #2

    Borek

    User Avatar

    Staff: Mentor

    I got 319 g, close enough.
     
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