- #1

rlay023

- 13

- 3

I found a previous post here that has helped me size an engine for a ski tow rope but wanted to take that a step further an add friction into the equation.

If I followed that problem corrected, the tow rope requires 821W calculated as follows:

power = work/time

work = mhg (272kg)(14m)*(9.8 m/s^2)

time = target speed of 5.5 ft/s, it will take 45.5 seconds to travel 250 feet.

.821kW *. 74569 = .61bHP required

The friction coefficient of snow/ice can range from .03 - .1 and the angle of ascent is 18.9%.

Can anyone help layer in the friction loss into the power calculation?